Suppose the number of cars that arrive at a car wash is described by a
Poisson distribution with a mean of 10 cars/per hour.
What is the probability that no car arrives within 2 hours?
Suppose the number of cars that arrive at a car wash is described by a
Poisson distribution with a mean of 10 cars/per hour.
What is the probability that 5 cars arrive within 20 minutes?
Suppose the number of cars that arrive at a car wash is described by a
Poisson distribution with a mean of 10 cars/per hour.
What is the probability that the time between the arrival is less than 30
minutes?
Given that Z is a standard normal random variable and X is a normal
random variable with mean 2 and variance 4.
P(−1.2 ≤ Z ≤ 2.5)
Given that Z is a standard normal random variable and X is a normal
random variable with mean 2 and variance 4.
P(−2.2 ≤ Z ≤ −1.24)
Given that Z is a standard normal random variable and X is a normal
random variable with mean 2 and variance 4.
P(−1 ≤ Z ≤ c) = 0.75 . Find c .
Given that Z is a standard normal random variable and X is a normal
random variable with mean 2 and variance 4.
P(1 ≤ X ≤ 4)
Given that Z is a standard normal random variable and X is a normal
random variable with mean 2 and variance 4.
P(c ≤ X) = 0.84 . Find c .
Find c .
Compute the mean of X .
Compute the variance of X .
Compute the mean.
Compute the standard deviation.
Compute the median.
Determine the interquartile range.
A survey of business students indicated that students who had spent at
least 3 hours studying per day had a probability of 0.85 of average scoring
above 80. Student who did not spend at least 3 hours studying per day had
a probability of 0.1 of average scoring above 80. It has been determined
that 5% of the business students had spent at least 3 hours studying per
day. Given that a student average scored above 85, what is the probability
that he/she had spent 3 hours studying per day?
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